Activity | to | tm | tp |
---|---|---|---|
1-2 | 6 | 9 | 12 |
1-3 | 3 | 4 | 11 |
2-4 | 2 | 5 | 14 |
3-4 | 4 | 6 | 8 |
3-5 | 1 | 1.5 | 5 |
2-6 | 5 | 6 | 7 |
4-6 | 7 | 8 | 15 |
5-6 | 1 | 2 | 3 |
Solution: First of all draw the network diagram for given data as shown below:
Here the time for completion of activities are probabilistic. So, using given values of time we will find the expected time to completion the activities and variance.
For each given activity we will calculate the expected time as follows:
Activity | to | tm | tp | Variance (V) | |
---|---|---|---|---|---|
1-2 | 6 | 9 | 12 | ||
1-3 | 3 | 4 | 11 | 5 | 1.778 |
2-4 | 2 | 5 | 14 | 6 | 4.000 |
3-4 | 4 | 6 | 8 | 6 | 0.444 |
3-5 | 1 | 1.5 | 5 | 2 | 0.444 |
2-6 | 5 | 6 | 7 | 6 | 0.111 |
4-6 | 7 | 8 | 15 | 9 | 1.778 |
5-6 | 1 | 2 | 3 | 2 | 0.111 |
Now based on estimate time, we calculate the EST, EFT, LST and LFT for each activity to find out critical path of project as shown below. (Click here to know about calculation of EST, EFT, LST and LFT from CPM numerical)
Activity | Duration | EST | EFT | LST | LFT | Total Float |
---|---|---|---|---|---|---|
1-2 | 9 | 0 | 9 | 0 | 9 | 0 |
1-3 | 5 | 0 | 5 | 4 | 9 | 4 |
2-4 | 6 | 9 | 15 | 9 | 15 | 0 |
3-4 | 6 | 5 | 11 | 9 | 15 | 4 |
3-5 | 2 | 5 | 7 | 20 | 22 | 15 |
2-6 | 6 | 9 | 15 | 18 | 24 | 9 |
4-6 | 9 | 15 | 24 | 15 | 24 | 0 |
5-6 | 2 | 7 | 9 | 22 | 24 | 15 |
Here the critical path is along the activities 1-2
, 2-4
, 4-6
. So the critical path is 1-2-4-6
. Following diagram is prepared to show critical path along with EST and LFT.
The critical path = 1-2-4-6 with time duration of 24 days.
Here standard deviation is calculated for activities of critical path. So we get
Now the probability of completion of project in that given time (t) of 26 days, can be calculate by below formula,
Using table in Appendix-B, we get probability
As you can see below in Appendix-B the first column Z that is the probability we find out in the example through formula. The second column represent the probability in percentage .
As we have value of now you can see in table we have which has and has we take average of both we get
As you can see for which is and for which is
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