Heat Engine, Heat Pump and Refrigerator Difference (Refrigeration and Air Conditioning) | Education Lessons

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Heat Engine, Heat Pump and Refrigerator Difference (Refrigeration and Air Conditioning)

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This topic is based on REFRIGERATION AND AIR CONDITIONING (RAC). Go ahead you are on the best path of learning. Here you will get the quality knowelwdge about the different engineering topics. This will be helpful to score good marks in your examinataion. The links of the related videos of RAC are given below: Bell-Coleman or Reverse Brayton or Joule Cycle with derivation [Part-1](RAC) https://youtu.be/adXogQXcEjc Bell-Coleman or Reverse Brayton or Joule Cycle with derivation[Part-2](RAC) https://youtu.be/lqpBu7ZF3lA Refrigeration & Air Conditioning (Refrigeration,Refrigerant,Air-conditioning)(RAC) [PART I] https://youtu.be/38gothWPTHg...Show less

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[Notes] Operation Research

Unbalanced Transportation Problem Numerical Modified Distribution Method (MODI) | Transportation Problem | Transportation Model Stepping Stone | Transportation Problem | Transportation Model Vogel’s Approximation Method (VAM) | Method to Solve Transportation Problem | Transportation Model Transportation Model - Introduction North West Corner Method | Method to Solve Transportation Problem | Transportation Model Least Cost Method | Method to Solve Transportation Problem | Transportation Model Tie in selecting row and column (Vogel's Approximation Method - VAM) | Numerical | Solving Transportation Problem | Transportation Model Assignment Model | Linear Programming Problem (LPP) | Introduction Critical Path Method [CPM] - Steps and Introduction | Network Analysis | Operation Research Crashing Special Case - Multiple (Parallel) Critical Paths Crashing Special Case - Indirect cost less than Crash Cost Basics of Program Evaluation and Review Technique (PERT)Numerical on PERT (Program Evaluation and Review Technique)Network Analysis - Dealing with Network Construction Basics Construct a project network with predecessor relationship | Operation Research | Numerical Graphical Method | Methods to solve LPP | Linear Programming Basics of Linear Programming Linear Programming Problem (LPP) Formulation with Numericals

[Notes] Dynamics of Machinery

Law of Parallelogram of Forces : 5 in 5 MCQs S01-E01 Variation of Tractive Force | Tractive Effort | Effect of Partial Balancing of Locomotives Balancing of V-Engines Concept of Direct and Reverse Crank for V-engines & Radial engines Static and Dynamic Balancing Multi Cylinder Inline Engine (with firing order) | Numerical Critically Damped System (ξ = 1)Damped free Vibration - Numerical 1 Damped free Vibration - Numerical 2 Damped free Vibration - Numerical 4 Logarithmic Decrement (δ)Over-Damped System (ξ>1)Under-Damped System (ξ < 1)

[Notes] Maths

tan (A + B) = √3 and tan (A -B) = 1/√3 | Trigonometry Numerical 15 cot A = 8 | Find the value of sin A and sec A | Trigonometry Numerical PQ = 12cm and PR = 13cm | Find tan P - cot R | Trigonometry Numerical cot θ = 7/8 | Find all other trigonometric ratios | Trigonometry Numerical Trigonometry Formulas | sin θ, cos θ, tan θ, cosec θ, sec θ, cot θ | Trigonometry Basics Find the value of (sin 30° + tan 45° - cosec 60°) / (sec 30° + cos 60° + cot 45°) and (5 cos² 60° + 4 sec² 30° - tan² 45°) / (sin² 30° + cos² 30°)In △PQR, PR + QR = 25cm and PQ = 5cm | Find the value of sin P, cos P, tan P | Trigonometry Numerical 3 cot A = 4 | Check if (1−tan²A)/(1+tan²A) = cos²A - sin²A | Trigonometry Numerical

[Notes] Science

Why Gravitational Acceleration g is 9.8 m/s² ? [Calculation]

[Notes] Computer Aided Design

Understanding the concept | Finite Element Method | Advantages of FEA | Disadvantages of FEA | Applications of FEA | Finite Element Analysis

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